Postcard Mixture
How would I solve these two word problems?
A shopper pays $20.75 for four pounds of a nut mixture consisting of almonds and pecans. If almonds cost $3.50 per pound and pecans cost $6.00 per pound, how much of each were purchased?
A recent mailing of 56 letters and postcards cost $21.72. If the letters cost 42 cents each to mail and postcards cost 27 cents each, how many of each were mailed?
Solve as a system of equations where x = weight of Almonds and y = weight of Pecans
The second equation is weight multiplied by price to give the total price of the mixed nuts.
x + y = 4
3.5x + 6y = 20.75
-------------------------
-6(x + y = 4) .....multiply by (-6) so that you can add the 2 equations isolating x
-6x - 6y = -24
3.5x + 6y = 20.75
-----------------------
-2.5x + 0y = -3.25
-2.5x/-25 = -3.25/-2.5 ... divide both sides by -2.5 to isolate x
x = 1.3
through substitution now find y
1.3 + y = 4
y = 4 - 1.3
y = 2.7
check your answer by inserting both values into the 2nd equation
3.5(1.3) + 6(2.7) = 20.75
4.55 + 16.20 = 20.75 check ... 1.3lbs Almonds 2.7lbs of Pecans
=============
2nd problem is the same type as the first
x = # of postcards y = # of letters
x + y = 56
.27x + .42y = 21.72
----------------------------
100(0.27x + 0.42y = 21.72) .... do this to eliminate the fractions.
x + y = 56
27x + 42y = 2172
---------------------------
-27( x + y = 56) .... multiply the equation by (-27) so that you can add the 2 equations isolating y to find the number of letters
-27x - 27y = -1512
27x + 42y = 2172
------------------------------
0x + 15y = 660
15y/15 = 660/15 ...divide both sides by 15 to isolate y
y = 44
through substitution now find x
x + 44 = 56
x = 56 - 44
x = 12
check your answer by inserting both values into the 2nd equation
.27(12) + .42(44) = 21.72
3.24 + 18.48 = 21.72 ......... check ... 12 postcards .. 44 letters
edited for clarity
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